Optimal. Leaf size=73 \[ \frac {a^3 \sin ^6(c+d x)}{6 d}+\frac {3 a^3 \sin ^5(c+d x)}{5 d}+\frac {3 a^3 \sin ^4(c+d x)}{4 d}+\frac {a^3 \sin ^3(c+d x)}{3 d} \]
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Rubi [A] time = 0.07, antiderivative size = 73, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, integrand size = 27, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.111, Rules used = {2833, 12, 43} \[ \frac {a^3 \sin ^6(c+d x)}{6 d}+\frac {3 a^3 \sin ^5(c+d x)}{5 d}+\frac {3 a^3 \sin ^4(c+d x)}{4 d}+\frac {a^3 \sin ^3(c+d x)}{3 d} \]
Antiderivative was successfully verified.
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Rule 12
Rule 43
Rule 2833
Rubi steps
\begin {align*} \int \cos (c+d x) \sin ^2(c+d x) (a+a \sin (c+d x))^3 \, dx &=\frac {\operatorname {Subst}\left (\int \frac {x^2 (a+x)^3}{a^2} \, dx,x,a \sin (c+d x)\right )}{a d}\\ &=\frac {\operatorname {Subst}\left (\int x^2 (a+x)^3 \, dx,x,a \sin (c+d x)\right )}{a^3 d}\\ &=\frac {\operatorname {Subst}\left (\int \left (a^3 x^2+3 a^2 x^3+3 a x^4+x^5\right ) \, dx,x,a \sin (c+d x)\right )}{a^3 d}\\ &=\frac {a^3 \sin ^3(c+d x)}{3 d}+\frac {3 a^3 \sin ^4(c+d x)}{4 d}+\frac {3 a^3 \sin ^5(c+d x)}{5 d}+\frac {a^3 \sin ^6(c+d x)}{6 d}\\ \end {align*}
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Mathematica [A] time = 0.28, size = 70, normalized size = 0.96 \[ -\frac {a^3 (-1200 \sin (c+d x)+520 \sin (3 (c+d x))-72 \sin (5 (c+d x))+870 \cos (2 (c+d x))-240 \cos (4 (c+d x))+10 \cos (6 (c+d x))-45)}{1920 d} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.46, size = 85, normalized size = 1.16 \[ -\frac {10 \, a^{3} \cos \left (d x + c\right )^{6} - 75 \, a^{3} \cos \left (d x + c\right )^{4} + 120 \, a^{3} \cos \left (d x + c\right )^{2} - 4 \, {\left (9 \, a^{3} \cos \left (d x + c\right )^{4} - 23 \, a^{3} \cos \left (d x + c\right )^{2} + 14 \, a^{3}\right )} \sin \left (d x + c\right )}{60 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.19, size = 58, normalized size = 0.79 \[ \frac {10 \, a^{3} \sin \left (d x + c\right )^{6} + 36 \, a^{3} \sin \left (d x + c\right )^{5} + 45 \, a^{3} \sin \left (d x + c\right )^{4} + 20 \, a^{3} \sin \left (d x + c\right )^{3}}{60 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.10, size = 58, normalized size = 0.79 \[ \frac {\frac {a^{3} \left (\sin ^{6}\left (d x +c \right )\right )}{6}+\frac {3 a^{3} \left (\sin ^{5}\left (d x +c \right )\right )}{5}+\frac {3 a^{3} \left (\sin ^{4}\left (d x +c \right )\right )}{4}+\frac {a^{3} \left (\sin ^{3}\left (d x +c \right )\right )}{3}}{d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.33, size = 58, normalized size = 0.79 \[ \frac {10 \, a^{3} \sin \left (d x + c\right )^{6} + 36 \, a^{3} \sin \left (d x + c\right )^{5} + 45 \, a^{3} \sin \left (d x + c\right )^{4} + 20 \, a^{3} \sin \left (d x + c\right )^{3}}{60 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 0.06, size = 57, normalized size = 0.78 \[ \frac {\frac {a^3\,{\sin \left (c+d\,x\right )}^6}{6}+\frac {3\,a^3\,{\sin \left (c+d\,x\right )}^5}{5}+\frac {3\,a^3\,{\sin \left (c+d\,x\right )}^4}{4}+\frac {a^3\,{\sin \left (c+d\,x\right )}^3}{3}}{d} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 5.14, size = 82, normalized size = 1.12 \[ \begin {cases} \frac {a^{3} \sin ^{6}{\left (c + d x \right )}}{6 d} + \frac {3 a^{3} \sin ^{5}{\left (c + d x \right )}}{5 d} + \frac {3 a^{3} \sin ^{4}{\left (c + d x \right )}}{4 d} + \frac {a^{3} \sin ^{3}{\left (c + d x \right )}}{3 d} & \text {for}\: d \neq 0 \\x \left (a \sin {\relax (c )} + a\right )^{3} \sin ^{2}{\relax (c )} \cos {\relax (c )} & \text {otherwise} \end {cases} \]
Verification of antiderivative is not currently implemented for this CAS.
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